python 토근처리

text = 'foo = 23 + 42 * 10'

tokens = [('NAME', 'foo'), ('EQ', '='), ('NUM', '23'), ('PLUS', '+'),
          ('NUM', '42'), ('TIMES', '*'), ('NUM', '10')]

import re
NAME = r'(?P<NAME>[a-zA-Z_][a-zA-Z_0-9]*)'
NUM = r'(?P<NUM>\d+)'
PLUS = r'(?P<PLUS>\+)'
TIMES = r'(?P<TIMES>\*)'
EQ = r'(?P<EQ>=)'
WS = r'(?P<WS>\s+)'

master_pat = re.compile('|'.join([NAME, NUM, PLUS, TIMES, EQ, WS]))

from collections import namedtuple
import json
Token = namedtuple('Token', ['type', 'value'])

def generate_tokens(pat, text):
    scanner = pat.scanner(text)
    for m in iter(scanner.match, None):
        yield Token(m.lastgroup, m.group())

for tok in generate_tokens(master_pat, 'foo = 42'):
    print(tok)

tokens = (tok for tok in generate_tokens(master_pat, text) if tok.type != 'WS')
#print(list(tokens))
jj = {}
for tok in tokens:
    #print(tok)
    #t = "'{0}':'{1}'".format(tok.type, tok.value)
    #t = ':'.join([tok.type, tok.value])
    jj[tok.type] = tok.value

print(jj)

jj2 = json.dumps(jj)
print(jj2)

print("")
# 테스트용 Dictionary
customer = {
    'id': 152352,
    'name': '강진수',
    'history': [
        {'date': '2015-03-11', 'item': 'iPhone'},
        {'date': '2016-02-23', 'item': 'Monitor'},
    ]
}

# JSON 인코딩
jsonString = json.dumps(customer)

# 문자열 출력
print(jsonString)
print(type(jsonString))  # class str